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15.9 : Multiple Halogenation of Methyl Ketones: Haloform Reaction

A method involving the transformation of methyl ketones to carboxylic acids using excess base and halogen is called the haloform reaction. It begins with the deprotonation of α hydrogen to form an enolate ion which reacts with the electrophilic halogen to give an α-halo ketone. The step continues until all the α protons are substituted to form a trihalomethyl ketone. The resulting molecule is unstable, and in the presence of a hydroxide base, it readily undergoes nucleophilic acyl substitution. This leads to the expulsion of trihalomethyl carbanion and produces carboxylic acid. The carbanion generated is stable owing to the electron-withdrawing effect of the three halogens. Subsequent deprotonation of the acid by carbanion forms a carboxylate and haloform, which is the driving force of the reaction. Finally, acidification of the carboxylate gives the desired product, and the reaction is named after the by-product. Using chlorine or bromine results in immiscible liquids of chloroform and bromoform. In contrast, iodine forms a yellow precipitate of iodoform, often used to detect methyl ketones in unknown substrates.

Tags

HalogenationMethyl KetonesHaloform ReactionEnolate IonElectrophilic HalogenAlpha halo KetoneTrihalomethyl KetoneHydroxide BaseNucleophilic Acyl SubstitutionCarboxylic AcidTrihalomethyl CarbanionElectron withdrawing EffectCarboxylateHaloform By productChlorineBromineIodineChloroformBromoformIodoform

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