Name: Method of Joints: Problem Solving II
Uploaded: 2023-09-22T11:49:24
Duration: 1 min 30 s
Description: Learn by watching this video about Method of Joints: Problem Solving II at JoVE.com

Consider a truss structure with frictionless joints fixed to a wall and roller support on ground. If a force of 150 N is applied to joint A, then determine the forces in each member of the truss.
The forces at each joint can be determined using the method of joints.
Firstly, the angle between the members AC and AB can be determined as the tan inverse of the ratio of the length of BC and AB.
Secondly, draw a free-body diagram of joint A and resolve the forces into their components. By applying the equations of equilibrium, the unknown forces can be determined.
Next, by drawing the free-body diagrams of joints B and C, and using equilibrium equations, the unknown forces at joints B and C can be determined.
Finally, draw a free-body diagram of joints D and E. For members CD and EF, resolve the forces into the horizontal and vertical components. The unknown forces at joints D and E can be determined using the equations of equilibrium.

<ol>
	<li>Hibbeler, R.C. (2016). Engineering Mechanics &#8210; Statics and Dynamics. Hoboken, New Jersey: Pearson Prentice Hall. pp 276-277.</li>
</ol>

method of joints: problem solving ii

Consider a truss structure with frictionless joints fixed to a wall and roller support. If a force of 150 N is applied to joint A, the forces in each member of the truss can be determined using the method of joints.
<img alt="Figure 1" src="/files/ftp_upload/14283/14283_PT_Fig_1v2.svg" style="text-align: center; height: 350px;" />
The angle between members AC and AB can be found by taking the inverse tangent of the ratio of the lengths of BC and AB, and the result obtained is 67.38&#176;. A free-body diagram of joint A is considered, and all unknown forces are resolved into their respective components.
The vertical force equilibrium condition can then be used to calculate the force acting on member CA, which is equal to 173.08 N.
<img alt="Equation 1" src="/files/ftp_upload/14283/14283_PT_Equation_1v2.svg" style="text-align: center; height: 15px;" />
Similarly, the horizontal force equilibrium condition can be used to find the force FAB as 161.54 N.
<img alt="Equation 2" src="/files/ftp_upload/14283/14283_PT_Equation_2v2.svg" style="text-align: center; height: 15px;" />
Free-body diagrams of joints B and C are considered, and the vertical and horizontal force equilibrium conditions are applied to calculate the unknown forces FBD , FCD , and FEC. The resulting values for FBD , FCD , and FEC are 161.53 N, 173.08 N and 207.70 N, respectively.
Free-body diagrams of joints D and E are finally considered, and the vertical and horizontal force equilibrium conditions are applied. This gives the values of FED and FDF as 138.46 N and 265.39 N, respectively.

Learn by watching this video about Method of Joints: Problem Solving II at JoVE.com

Method of Joints: Problem Solving II

Consider a truss structure with frictionless joints fixed to a wall and roller support. If a force of 150 N is applied to joint A, the forces in each ...