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6.7 : Method of Sections

Consider a truss structure, as shown in the figure.

Truss static equilibrium diagram; forces F1, F2 shown; structural analysis concept.

Forces F1 and F2 act at joints B and D, respectively. The method of sections can be employed to determine the forces acting on specific members of the truss, such as EF, DC, and DF. This approach is based on the principle that a truss in equilibrium also has each of its segments in equilibrium.

To calculate the forces acting on these members, a free-body diagram of the truss is considered. The equilibrium equation for moments about joint A can be applied to estimate the support reaction at point E.

Static equilibrium equation diagram: Σ(F × r)=0, illustrating torque balance concepts.

A cut is made along a sectional plane that intersects a maximum of three members: EF, DC, and DF. Next, a free-body diagram of the right side of the cut section is drawn, assuming the unknown forces as tensile.

Static equilibrium diagram, forces and angles in a mechanical system, ΣFx=0, vector illustration.

A solution for the force acting on member EF can be obtained by summing moments about joint D.

Static equilibrium equation; vector representation, torque balance, physics formula, mechanical system.

The unknown inclined forces, FDC and FDF, are resolved into horizontal and vertical components. Applying the equilibrium condition for the forces along the horizontal and vertical directions results in two separate equations.

Static equilibrium equation: \( F_{DC}\cos\theta + F_{DF}\sin\theta - F_2 = 0 \).

Static equilibrium equation; \( F_{DC}\sinθ - F_{DF}\cosθ + R_E = 0 \); physics formula analysis.

The forces along members DC and DF can be estimated by solving these simultaneous equations.

Tags

Method Of SectionsTruss StructureForces F1 And F2Joints B And DFree body DiagramEquilibrium EquationSupport ReactionMembers EFDCDFTensile ForcesSumming MomentsInclined ForcesHorizontal ComponentsVertical ComponentsSimultaneous Equations

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