Войдите в систему

Consider a jib crane with an external load suspended from the pulley. The dimensions of the crane members are shown in the figure. A systematic analysis of the frame structure is required to determine the reaction forces at the pin joints, assuming that the pulleys are frictionless.

Figure 1

The system has two main structural components: a two-force member BD and a multi-force member ABC. The two-force member BD refers to a straight element subjected only to forces at its two ends, B and D, with no additional forces acting along its length. These forces are equal in magnitude but opposite in direction, resulting in the member being either in pure tension or compression. On the other hand, the multi-force member ABC is subjected to more than two forces distributed along its length. These forces may include external loads, reaction forces at pin joints, and the force exerted by the cable. Due to multiple forces acting on member ABC, it experiences a more complex stress distribution compared to the simpler two-force member BD.

Figure 2

Considering the lower pulley section, the load weight balances the tension in the cables resulting in an upward tension of 10 kN for each cable. Now, considering the upper pulley section, the tension T in the vertical cable is directed downwards, while it points towards joint A for the horizontal cable. The tension in the vertical cable is also 10 kN as it is part of the same continuous cable system.

In member DB, the force FBD can be resolved into its horizontal and vertical components using a slope triangle. The moment equilibrium condition at joint A gives FBD as 50 kN.

The horizontal force equilibrium condition can be applied to joint A.

Equation 1

Substituting the values of the length AB, AC, and radius of the pulley C, the force FBD is obtained as 50 kN.

The horizontal force equilibrium condition gives the reaction force at A as 40 kN.

Equation 2

Similarly, using the vertical force equilibrium condition, the vertical reaction force at A is estimated as -20 kN.

Equation 3

The force equilibrium conditions can be applied at joint D to obtain the horizontal and vertical reaction forces at D.

Equation 4

Equation 5

The obtained results indicate that the horizontal and vertical reaction forces at point D are -30 kN and 40 kN, respectively.

Теги
Jib CraneExternal LoadPulleyReaction ForcesPin JointsTwo force MemberMulti force MemberTensionCompressionStress DistributionLoad WeightTension CablesForce ComponentsMoment EquilibriumForce Equilibrium ConditionsHorizontal Reaction ForceVertical Reaction Force

Из главы 6:

article

Now Playing

6.13 : Frames: Problem Solving I

Structural Analysis

355 Просмотры

article

6.1 : Введение в структуры

Structural Analysis

914 Просмотры

article

6.2 : Простые фермы

Structural Analysis

1.5K Просмотры

article

6.3 : Метод суставов

Structural Analysis

644 Просмотры

article

6.4 : Метод суставов: решение проблем I

Structural Analysis

939 Просмотры

article

6.5 : Метод суставов: решение проблем II

Structural Analysis

439 Просмотры

article

6.6 : Член с нулевой силой

Structural Analysis

1.2K Просмотры

article

6.7 : Метод разделов

Structural Analysis

509 Просмотры

article

6.8 : Метод разделов: Решение проблем I

Structural Analysis

435 Просмотры

article

6.9 : Метод разделов: Решение проблем II

Structural Analysis

832 Просмотры

article

6.10 : Космические фермы

Structural Analysis

710 Просмотры

article

6.11 : Космические фермы: решение проблем

Structural Analysis

523 Просмотры

article

6.12 : Кадров

Structural Analysis

473 Просмотры

article

6.14 : Фреймы: решение проблем II

Structural Analysis

162 Просмотры

article

6.15 : Машины

Structural Analysis

215 Просмотры

See More

JoVE Logo

Исследования

Образование

О JoVE

Авторские права © 2025 MyJoVE Corporation. Все права защищены